AP Physics 1 Week 2 (June 18 - June 24, 2017)

Category: Week 2 (06/18 - 06/24) Due June 24

06/04/2017
06/24/2017

Part 1:  Algebra (Rearrange)


1.  v2 = v02 + 2a(x − x0)  solve for x

2.  θ = θ0 + ω0t + ½αt2  solve for α

3. 

P1 + ρgy1 + ½ρv12 =  P2 + ρgy2 + ½ρv2

solve for g

4.  Kmax = E − ϕ = h(ƒ − ƒ0)  solve for ƒ0

5. 

1  = −R 
1  −  1
λ n2 n02

solve for no

Part 2:  Algebra (Plug and Chug)

6.  v2 = v02 + 2a(x − x0) 
     v = 25, v0 = 0, x = 35.4, x0 = 0, solve for a

7.  θ = θ0 + ω0t + ½αt2 
     θ = 900, θ0 = 200, t = 0.378, α = 0.564, solve  for ω0

8. 

P1 + ρgy1 + ½ρv12 =  P2 + ρgy2 + ½ρv2

P1 = 640,000, P2 = 250,000 p =1000, g = 9.8, y1 = 50, v1 = 7.65, y2 = 25, solve for v2

9.  Kmax = E − ϕ = h(ƒ − ƒ0) h = 6.626 x 10-34
solve for Kmax if , ƒ = 1.35 x 1012, ƒ0 = 1.26 x 1012

10. 

1  = −R 
1  −  1
λ n2 n02

R = 1.097 x 107, n = 5, n0 = 2, solve for l



Part 3: Geometry/Trigonometry
(For Physics, make sure your calculator is set in degrees)

In your math class, you learned the unit circle based on the Babylonian (historical scale) reading counter-clockwise, 0 degrees is positive x or east, 90 degrees is positive y or north, 180 degrees is negative x or west, 270 degrees is negative y or south, back to positive x is 360 degrees.  The Babylonian scale was based on the sun rising in the east (zero degrees), and setting in the west (180 degrees).  The Babylonian number scale was based on 12 rather than 10's.  Physics, a very precise form of astronomy uses compass measurements instead.  Instead of counterclockwise, we read clockwise from north.  North is 0 compass degrees, east is 90 compass degrees, south is 180 compass degrees, and west is 270 compass degrees.  Back to a northward direction, is 360 compass degrees.


Given each Babylonian angle, determine the compass direction for each.  Next, determine the cosine and sine for both the Babylonian angle and the compass degree.

11.  55 degrees

12.  125 degrees

13.  250 degrees

14.  325 degrees

15.  670 degrees


Part 4:  Word Problems

speed = (distance / time) or speed x time = distance,  speed is a "rate"

Special Note:  WKP and WKS is the first letter of the authors last name of the textbook this problem was taken.
 
Need help:   check out:
 
 
http://www.onlinemathlearning.com/distance-problems.html
 

16. How far west can a pilot go and return in 3 hours if his speed in still air is 450 mph when there is a wind blowing from the west at 50 mph?
(WKS, p120, #10)

 
17. Frank can walk a mile in 3 minutes less time than his sister and he can walk 5 miles while his sister walks 4 miles. Find the speed of each.
(WKS, p121, #25)
 

18. Albert and Bob run a race of 440 yards. In the first trial, Albert gave Bob a start of 65 yards and Albert won by 20 seconds. In the second trial, Albert gave Bob a start of 34 seconds and Bob won by 8 yards. Find the speeds of Albert and Bob in yards per second.  Assume that both Albert and Bob run the same rate in both trials. (WKS, p185, #5)

 

19. The time going 180 miles to the beach was 1 hour more than the time returning home. Find the speed in each direction if the rate returning home was 15 mph faster than the speed going to the beach. (WKS, p274 #1)

 
20. The highway distance between two cities is 280 miles. The speed for 80 miles of the trip from one city to the other is 10 mph faster than the speed for the remainder of the distance. Find the two speeds if the total time of the trip is 6 hours? (WKS, p274, #2)